class: center, middle, inverse, title-slide # ECON 3818 ## Chapter 12 ### Kyle Butts ### 27 September 2021 --- class: clear, middle <!-- Custom css --> <style type="text/css"> /* ------------------------------------------------------- * * !! 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</script> <style> .purple {color: #5601A4;} .navy {color: #0D3D56;} .ruby {color: #9A2515;} .alice {color: #107895;} .daisy {color: #EBC944;} .coral {color: #F26D21;} .kelly {color: #829356;} .jet {color: #131516;} .asher {color: #555F61;} .slate {color: #314F4F;} .cranberry {color: #E64173;} </style> ## Chapter 12: Introducing Probability --- # Randomness What is randomness? A phenomenon is .hi.purple[random] if: 1. Individual outcomes are uncertain 2. Has a distributions of outcomes in a large number of repetitions .it[Example]: A coin toss --- # Probability .hi.cranberry[Probability]: proportion of times a particular outcome would occur in a very long series of repetitions. - .it[Example]: What is the .cranberry[probability] of a coin landing on heads? For a given observation, the .cranberry[probability] that an .coral[event] occurs is: `$$\frac{\text{Number of ways event could occur}}{\text{Number of total possible outcomes}}$$` --- # Probability and Randomness <img src="data:image/png;base64,#ch12_files/figure-html/coin-toss-1.svg" width="100%" style="display: block; margin: auto;" /> --- # Probability Models We think of probability utilizing a particular framework, first we define a few useful terms: - .hi.kelly[Sample Space]: set of all possible outcomes - .hi.coral[Event]: outcome (or set of outcomes) of a random phenomenon - .coral[Event] is a subset of the .kelly[sample space] - .hi.cranberry[Probability Model]: assigns a probability to every .coral[event] in the .kelly[sample space] --- # Probability: Example Say we roll two six-sided die, the following would be our .kelly[sample space]: <img src="data:image/png;base64,#twodiesamplespace.png" width="75%" style="display: block; margin: auto;" /> Each outcome is equally likely, specifically each outcome has .cranberry[probability] of 1/36 --- # Clicker Question If I roll two six-sided die, what is the .cranberry[probability] I roll a one and a two? <ol type = "a"> <li>1/36</li> <li>2/36</li> <li>3/36</li> <li>4/36</li> </ol> --- # Set Notation `\(\coral{A} = \{1,2,3\}\)`, `\(\coral{B}=\{3,4,5\}\)`, `\(\coral{C}=\{1,2,3,4,5,6\}\)`, `\(\coral{D}=\{4\}\)` `\(\in\)`: "belongs to" - Example: `\(1 \in \coral{A}\)` `\(\notin\)`: "does not belong to" - Example: `\(4 \notin \coral{A}\)` `\(\cup\)`: Union; combination of two or more sets; "or" - Example: `\(\coral{A} \cup \coral{B} = \{1,2,3,4,5\}\)` `\(\cap\)`: Intersection; overlap of two or more sets; "and" - Example: `\(\coral{A} \cap \coral{B} = \{3\}\)` --- # Set Notation, cont. `\(\coral{A} = \{1,2,3\}\)`, `\(\coral{B}=\{3,4,5\}\)`, `\(\coral{C}=\{1,2,3,4,5,6\}\)`, `\(\coral{D}=\{4\}\)` `\(\coral{A}^c\)`: "A complement" - Example: `\(\coral{A}^c = \{x: x \notin \coral{A} \} = \{4,5,6\}\)` - Interpreted as "not .coral[A]" `\(\subseteq\)`: Subset - Example: `\(\coral{A} \subseteq \coral{C}\)`, however `\(\coral{C} \not\subseteq \coral{A}\)`. `\(\coral{\emptyset}\)`: is the null or empty set - contains nothing `\(\coral{A} \cap \coral{D}= \emptyset\)`: Disjoint --- # Clicker Question Given the following sets, `\(\coral{A}=\{5,10,15,20\}\)` and `\(\coral{B}=\{1,2,3,4,5\}\)` Which of the following is true? <ol type = "a"> <li>\(\coral{A} \cup \coral{B} = \{1,2,3,4,5,10,15,20\}\)</li> <li>\(\coral{A} \cup \coral{B} = \{5\}\)</li> <li>\(\coral{A} \cap \coral{B} = \{5\}\)</li> <li>\(\coral{A} \cap \coral{B} = \{1,2,3,4,5,10,15,20\}\)</li> <li>Both a. and c.</li> </ol> --- # Axioms of Probability Let `\(\coral{A}\)` and `\(\coral{B}\)` be .coral[events], and `\(P(\coral{A})\)` and `\(P(\coral{B})\)` are the .cranberry[probability] of those outcomes. We have a set of rules: 1. Any .cranberry[probability] is a number between 0 and 1 2. All possible outcomes together must have the .cranberry[probability] of 1 3. If two .coral[events] are disjoint, `$$P(\coral{A} \cap \coral{B})=0 \implies P(\coral{A} \cup \coral{B}) = P(\coral{A}) + P(\coral{B})$$` 4. `\(P(\coral{A}^c)=1-P(\coral{A})\)` --- # Clicker Question Given the three following scenarios: - A person is randomly selected. .coral[A] is the .coral[event] they are under 18. .coral[B] is the .coral[event] they are over 18. - A person is selected at random. .coral[A] is the .coral[event] that they earn more than $100,000 per year. .coral[B] is the .coral[event] that they earn more than $250,000. - A pair of dice are tossed. .coral[A] is the .coral[event] that one of the die is a 3. .coral[B] is the .coral[event] that the sum of two dice is 3. In which cases are the .coral[events], A and B, disjoint? <ol type = "a"> <li>1 only</li> <li>2 only</li> <li>3 only</li> <li>1 and 2</li> <li>1 and 3</li> </ol> --- # De Morgan's Law .hi.slate[De Morgan's law] of union and intersection. For any two finite sets .coral[A] and .coral[B]: 1. `\((\coral{A} \cup \coral{B})^c = \coral{A}^c \cap \coral{B}^c\)` 2. `\((\coral{A} \cap \coral{B})^c = \coral{A}^c \cup \coral{B}^c\)` --- # De Morgan's Law Example Let `\(\kelly{S}=\{j, k, l, m, n\}\)` and `\(\coral{A}=\{j, k, m\}\)` and `\(\coral{B}=\{k, m, n\}\)` 1. `\((\coral{A} \cup \coral{B})^c = (\coral{A}^c \cap \coral{B}^c)\)` <ol type="i"> <li> \((\coral{A} \cup \coral{B})= \{j, k, m, n\} \implies (\coral{A} \cup \coral{B})^c=\{l\}\) </li> <br/> <li> \(\coral{A}^c = \{l, n\}\) and \(\coral{B}^c=\{j, l\} \implies \coral{A}^c \cap \coral{B}^c = \{l\}\) </li> </ol> 2. `\((\coral{A} \cap \coral{B})^c = \coral{A}^c \cup \coral{B}^c\)` <ol type="i"> <li> \( (\coral{A} \cap \coral{B})=\{k,m\} \implies (\coral{A} \cap \coral{B})^c=\{j, l, n\} \) </li> <br/> <li> \( \coral{A}^c \cup \coral{B}^c=\{l, n\} \cup \{j, l\} \implies \coral{A}^c \cup \coral{B}^c = \{j, l, n\} \) </li> </ol> --- # Random Variables .hi.purple[Random variable]: variable whose value is a numerical outcome of a random phenomenon - .hi.purple[Random variables] can be .hi[discrete] or .hi[continuous] .it[Example:] Coin toss - `\(X\)` can be defined as the number of heads we see in two tosses: - `\(X\)` is a discrete random variable; `\(X=0,1,2\)` .hi.cranberry[Probability distribution]: tell us what values random variable X can take, and how to assign probabilities to those values --- # Example Flip a coin two times .kelly[Sample space]: - {.coral[(Head, Tail)], .coral[(Head, Head)], .coral[(Tail, Head)], .coral[(Tail, Tail)]} What is the .cranberry[probability] of each .coral[event]? --- # Clicker Question If I toss a coin two times, and `\(X\)` is the number of heads, then what is `\(P(\coral{X=2})\)`? <ol type = "a"> <li>1/4</li> <li>1/2</li> <li>3/4</li> <li>5/4</li> </ol> --- # Additional Examples Still flipping a coin twice, what is the .cranberry[probability] of getting at least one head? `\(P(\coral{X=1}) + P(\coral{X=2}) = 1-P(\coral{X=0})\)` - Now I only have to calculate one .cranberry[probability]! --- # Additional Dice Example What is the .cranberry[probability] of rolling a 7, 11, or double when rolling two dice? - Axiom 3 tells us we can find probabilities simply by adding if the .coral[event] is disjoint. .coral[Roll a 7]: `\(\left\{(1,6), (6,1), (2, 5), (5,2), (3,4), (4,3) \right\}\)` .coral[Roll a 11]: `\(\left\{(5,6), (6,5) \right\}\)` .coral[Roll a double]: `\(\left\{(1,1), (2,2), (3,3), (4,4), (5,5), (6,6) \right\}\)` - Are all 3 .coral[events] disjoint? --- # Additional Dice Example .coral[Roll a 7]: `\(\left\{(1,6), (6,1), (2, 5), (5,2), (3,4), (4,3) \right\}\)` .coral[Roll a 11]: `\(\left\{(5,6), (6,5) \right\}\)` .coral[Roll a double]: `\(\left\{(1,1), (2,2), (3,3), (4,4), (5,5), (6,6) \right\}\)` `\(P(\coral{7}) + P(\coral{11}) + P(\coral{\text{doubles}})=\frac{6}{36}+\frac{2}{36}+\frac{6}{36} \approx 0.4\)`